Gen and Particular Solution
Gen and Particular Solution
Last updated at December 16, 2024 by Teachoo
Transcript
Ex 9.2, 10 In each of the Exercises 1 to 10 verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation : š¦=ā(š^2āš„^2 ) š„ ā (āš , š) : š„+š¦ šš¦/šš„=0(š¦ā 0) š¦=ā(š^2āš„^2 ) Differentiating Both Sides w.r.t š„ šš¦/šš„=(š(ā(š^2 ā š„^2 )))/šš„ =1/(2ā(š^2 ā š„^2 ))Ć(ā2š„) =(āš„)/ā((š^2 ā š„^2 ) ) (Using Chain Rule) Now, We Have to Verify š„+š¦ šš¦/šš„=0 Taking LHS š„+š¦ šš¦/šš„ =š„+š¦[(āš„)/ā(š^2 ā š„^2 )] =š„+ā(š^2āš„^2 ) [(āš„)/ā(š^2 ā š„^2 )] =š„āš„ =0 = R.H.S Hence Verified (ā(šš ššš ) š¦=ā(š^2āš„^2 ))