# Example 16 - Chapter 6 Class 11 Linear Inequalities

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Example 16 Solve 8 5x 3 < 7. 8 5x 3 < 7 Adding 3 all sides (Eliminating -3) 8 + 3 5x 3 + 3 < 7 + 3 5 5x < 10 Dividing 5 all sides (Eliminating 5) 5 5 5 5 < 10 5 1 x < 2 Thus, x is a real number which is less than 2 and greater than or equal to 1 Hence, x [ 1, 2) is the solution

Solving inequality (both sides)

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.