Slide6.JPG

Slide7.JPG

Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


Transcript

Misc 4 Solve the inequality −15 < (3(𝑥 − 2))/5 ≤ 0 −15 < (3(𝑥 − 2))/5 ≤ 0 Multiplying 5 all sides (Eliminating 5) −15 × 5 < 5 × (3(𝑥 − 2))/5 ≤ 5 × 0 –75 < 3(x – 2) ≤ 0 Dividing 3 all sides (Eliminating 3) (−75)/3 < (3(𝑥 − 2))/3 ≤ 0/3 –25 < x – 2 ≤ 0 Adding 2 all sides (Eliminating 2) – 25 + 2 < x – 2 + 2 ≤ 0 + 2 –23 < x ≤ 2 Thus, x is a real number which is less than or equal to 2 and greater than −23 Hence, x ∈ (–23, 2] is the solution

Ask a doubt
Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.