# Ex 6.1, 25

Last updated at March 9, 2017 by Teachoo

Last updated at March 9, 2017 by Teachoo

Transcript

Ex 6.1, 25 The longest side of a triangle is 3 times the shortest side and the third side is 2 cm shorter than the longest side. If the perimeter of the triangle is at least 61 cm, find the minimum length of the shortest side. Let the length of the shortest side be x cm. So, length of longest side = 3 times shorter side = 3x & Length of the third side = (3x – 2) cm Now, Perimeter = Sum of three sides = x + 3x + (3x – 2) = x + 3x + 3x – 2 = 7x – 2 Given that, perimeter of the triangle is at least 61 cm, i.e. Perimeter ≥ 61 7x – 2 ≥ 61 7x ≥ 61 + 2 7x ≥ 63 𝑥 ≥ 637 x ≥ 9 ∴ Minimum value of x is 9 Thus, the minimum length of the shortest side is 9 cm.

Class 11

Important Question for exams Class 11

- Chapter 1 Class 11 Sets
- Chapter 2 Class 11 Relations and Functions
- Chapter 3 Class 11 Trigonometric Functions
- Chapter 4 Class 11 Mathematical Induction
- Chapter 5 Class 11 Complex Numbers
- Chapter 6 Class 11 Linear Inequalities
- Chapter 7 Class 11 Permutations and Combinations
- Chapter 8 Class 11 Binomial Theorem
- Chapter 9 Class 11 Sequences and Series
- Chapter 10 Class 11 Straight Lines
- Chapter 11 Class 11 Conic Sections
- Chapter 12 Class 11 Introduction to Three Dimensional Geometry
- Chapter 13 Class 11 Limits and Derivatives
- Chapter 14 Class 11 Mathematical Reasoning
- Chapter 15 Class 11 Statistics
- Chapter 16 Class 11 Probability

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CA Maninder Singh

CA Maninder Singh is a Chartered Accountant for the past 8 years. He provides courses for Practical Accounts, Taxation and Efiling at teachoo.com .