1. Class 11
2. Important Question for exams Class 11
3. Chapter 6 Class 11 Linear Inequalities

Transcript

Misc 13 How many litres of water will have to be added to 1125 litres of the 45% solution of acid so that the resulting mixture will contain more than 25% but less than 30% acid content? Volume of existing solution = 1125 litres Amount of acid in it = 45% of 1125 Hence, amount of water in it = 55% of 1125 = 55 100 1125 Let amount of water added be x litres So, Volume of new solution = 1125 + x Now, given that the new solution will contain more than 25% acid content Hence, 25 % of (1125 + x) = 506.25 25 % (1125 + x) = 506.25 25 100 (1125 + x) = 506.25 1 4 (1125 + x) = 506.25 1 4 (1125 + x) = 506.25 (1125 + x) = 506.25 4 1125 + x = 2025 x = 2025 1125 x = 900 Similarly, maximum acid content is 30% Hence, 30 % of (1125 + x) = 506.25 30 % (1125 + x) = 506.25 30 100 (1125 + x) = 506.25 3 10 (1125 + x) = 506.25 (1125 + x) = 506.25 10 3 (1125 + x) = 1687.5 x = 1687.5 1125 x = 562.5 Hence, acid content should be between 25% and 30% i.e. amount of water added should be between 900 & 562.5 litres i.e. 562.5 < x < 900

Chapter 6 Class 11 Linear Inequalities

Class 11
Important Question for exams Class 11