# Ex 10.1, 5 - Chapter 10 Class 11 Straight Lines (Important Question)

Last updated at Feb. 3, 2020 by Teachoo

Last updated at Feb. 3, 2020 by Teachoo

Transcript

Ex 10.1, 5 Find the slope of a line, which passes through the origin, and the mid-point of the line segment joining the points P (0, –4) & B (8, 0). We need to find Slope of a line passing through origin O (0, 0) & mid point of P (0, –4) & B (8, 0) Let M be the mid point of P (0, –4) & B (8, 0) We know that mid point of (x1, y1) and (x2, y2) = ((𝑥1 + 𝑥2 )/2,(𝑦1 + 𝑦2)/2) Mid point M of (0, –4) & (8, 0) = ((0 + 8)/2, ( − 4 + 0)/2) = (8/2, (−4)/2) = (4, –2) We know that slope of line passing through (x1, y1) and (x2, y2) is m = (𝑦_2 − 𝑦_1)/(𝑥_2 − 𝑥_1 ) Slope of line between points O (0, 0) & M (4, –2) Here, x1 = 0, y1 = 0 x2 = 4, y2 = –2 Putting values m = ( − 2 − 0)/(4 − 0) = ( −2)/4 = ( −1)/2 Hence slope of line is (−𝟏)/𝟐

Chapter 10 Class 11 Straight Lines

Ex 10.1, 5
Important
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Ex 10.1, 7 Important

Ex 10.1, 9 Important

Ex 10.1, 13 Important

Ex 10.2, 8 Important

Ex 10.2, 14 Important

Ex 10.2, 18 Important

Example 15 Important

Ex 10.3, 5 Important

Ex 10.3, 8 Important

Ex 10.3, 10

Ex 10.3, 16 Important

Ex 10.3, 18 Important

Example 22 Important

Misc 6 Important

Misc 12 Important

Misc 18 Important

Misc 23

Class 11

Important Questions for exams Class 11

- Chapter 1 Class 11 Sets
- Chapter 2 Class 11 Relations and Functions
- Chapter 3 Class 11 Trigonometric Functions
- Chapter 4 Class 11 Mathematical Induction
- Chapter 5 Class 11 Complex Numbers
- Chapter 6 Class 11 Linear Inequalities
- Chapter 7 Class 11 Permutations and Combinations
- Chapter 8 Class 11 Binomial Theorem
- Chapter 9 Class 11 Sequences and Series
- Chapter 10 Class 11 Straight Lines
- Chapter 11 Class 11 Conic Sections
- Chapter 12 Class 11 Introduction to Three Dimensional Geometry
- Chapter 13 Class 11 Limits and Derivatives
- Chapter 14 Class 11 Mathematical Reasoning
- Chapter 15 Class 11 Statistics
- Chapter 16 Class 11 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.