Ex 9.2, 17 - P (a, b) is mid-point of a line segment axes - Ex 9.2

part 2 - Ex 9.2, 17 - Ex 9.2 - Serial order wise - Chapter 9 Class 11 Straight Lines
part 3 - Ex 9.2, 17 - Ex 9.2 - Serial order wise - Chapter 9 Class 11 Straight Lines
part 4 - Ex 9.2, 17 - Ex 9.2 - Serial order wise - Chapter 9 Class 11 Straight Lines
part 5 - Ex 9.2, 17 - Ex 9.2 - Serial order wise - Chapter 9 Class 11 Straight Lines

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Ex 9.2, 17 P (a, b) is the mid-point of a line segment between axes. Show that equation of the line is š‘„/š‘Ž + š‘¦/š‘ = 2 Plotting x-axis and y-axis Let l be a line intersecting x-axis at A and y-axis at B Let P(a, b) be midpoint of AB Here Let co-ordinates of A be (p, 0) Let co-ordinates of B be (0, q) We know that mid point of a line joining points (x1, y1) & (x2, y2) is ((š‘„_1 āˆ’ š‘„_2 )/2, (š‘¦_1 āˆ’ š‘¦_2)/2) Mid point of a line joining points A (p,0) & B(0, q) is P(a,b) Putting values (a, b) = ((š‘ + 0)/2, (0 + š‘ž)/2) (a, b) = (š‘/2, š‘ž/2) So, p = 2a, q = 2b So, points A = (p, 0) = (2a, 0) B = (0, q) = (0, 2b) Finding equation of line by two point equation of line (y – y1) = (š‘¦_2 āˆ’ š‘¦_1)/(š‘„_2 āˆ’ š‘„_1 ) (x – x1) For equation of line l passing through (2a, 0) & (0, 2b) Here x1 = 2a, y1 = 0 x2 = 0, y2 = 2b Putting values (y – y1) = (š‘¦_2 āˆ’ š‘¦_1)/(š‘„_2 āˆ’ š‘„_1 ) (x – x1) (y – 0) = (2š‘ āˆ’ 0)/(0 āˆ’ 2š‘Ž) ( x – 2a) y = 2š‘/(āˆ’2š‘Ž) (x – 2a) y = (āˆ’b)/a (x – 2a) ay = –bx + 2ab ay + bx = 2ab Dividing by ab š‘Žš‘¦/š‘Žš‘ + š‘š‘„/š‘Žš‘ = 2š‘Žš‘/š‘Žš‘ š‘¦/š‘ + š‘„/š‘Ž = 2 š‘„/š‘Ž + š‘¦/š‘ = 2 Hence, the equation of line is š‘„/š‘Ž + š‘¦/š‘ = 2 Hence proved

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo