Example 10 - 9x2 + 4y2 = 36, find foci, vertices, length - Examples

part 2 - Example 10 - Examples - Serial order wise - Chapter 10 Class 11 Conic Sections
part 3 - Example 10 - Examples - Serial order wise - Chapter 10 Class 11 Conic Sections part 4 - Example 10 - Examples - Serial order wise - Chapter 10 Class 11 Conic Sections

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Example 10 Find the coordinates of the foci, the vertices, the lengths of major and minor axes and the eccentricity of the ellipse 9x2 + 4y2 = 36. Given 9x2 + 4y2 = 36 Dividing whole equation by 36 (9š‘„^2 + 4š‘¦^2)/36 = 36/36 9/36 x2 + (4š‘¦^2)/36 = 1 š‘„^2/4 + š‘¦^2/9 = 1 Since 4 < 9 Hence the above equation is of the form š‘„^2/š‘^2 + š‘¦^2/š‘Ž^2 = 1 Comparing (1) & (2) We know that c = √(a2āˆ’b2) c = √(9āˆ’4) c = āˆššŸ“ Co-ordinate of foci = (0, ± c) = (0, ± √5) So co-ordinates of foci (0, āˆššŸ“), & (0, āˆ’āˆššŸ“) Vertices = (0, ± a) = (0, ± 3) So, Vertices are (0, 3) & (0, āˆ’3) Length of major axis = 2a = 2 Ɨ 3 = 6 Length of minor axis = 2b = 2 Ɨ 2 = 4 Eccentricity e = c/a = āˆššŸ“/šŸ‘ Length of latus rectum = 2b2/a = (2 Ɨ 4)/3 = šŸ–/šŸ‘

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