Misc 19 - Chapter 13 Class 12 Probability (Term 2)
Last updated at Aug. 11, 2021 by
Transcript
Misc 19 If A and B are any two events such that P(A) + P(B) P(A and B) = P(A), then (A) P(B|A) = 1 (B) P(A|B) = 1 (C) P(B|A) = 0 (D) P(A|B) = 0 Here P(A and B) = P(A B) Now, P(A) + P(B) P(A and B) = P(A) P(A) + P(B) P(A B) = P(A) P(B) P(A B) = P(A) P(A) P(B) P(A B) = 0 P(B) = P(A B) P(B) = P(A B) Dividing By P(B) 1 = ( ) ( ) ( ) ( ) = 1 Also, P(A|B) = ( ) ( ) So, P(A|B) = 1 Hence, Option (B) is Correct.
Chapter 13 Class 12 Probability (Term 2)
Concept wise
-
Conditional Probability - Values given
- Conditional Probability - Statement
- Multiplication rule of probability
- Independent events
- Basic Probability
- Theorem of total probability
- Bayes theorem
- Random Variable - Defination
- Probability distribution
- Mean or Expectation of random variable
- Variance and Standard Deviation of a Random Variable
- Bernoulli Trials
- Binomial Distribution
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.
