Last updated at May 25, 2021 by
Transcript
Ex 13.1, 1 Given that E and F are events such that P(E) = 0.6, P(F) = 0.3 and P(E β© F) = 0.2, find P (E|F) and P(F|E)Given, P(E) = 0.6 P(F) = 0.3 & P(E β© F ) = 0.2 So, P(F β© E) = P(E β© F) = 0.2 P(E|F) = (π(πΈ β© πΉ))/(π(πΉ)) = 0.2/0.3 = π/π P(F|E) = (π(πΉ β© πΈ))/(π(πΈ)) = 0.2/0.6 = 2/6 = π/π
Conditional Probability - Values given
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