Ex 13.2, 8 - Let A, B be independent P(A) = 0.3, P(B) = 0.4

Ex 13.2, 8 - Chapter 13 Class 12 Probability - Part 2
Ex 13.2, 8 - Chapter 13 Class 12 Probability - Part 3


Transcript

Ex 13.2, 8 Let A and B be independent events with P (A) = 0.3 and P(B) = 0.4. Find (i) P(A ∩ B) (ii) P(A ∪ B) (iii) P (A|B) (iv) P (B|A)Given, P(A) = 0.3 , P(B) = 0.4 Since events A and B are independent ∴ P(A ∩ B) = P(A) . P(B) P(A ∩ B) = P(A) . P(B) = 0.3 × 0.4 = 0.12 P(A ∪ B) = P(A) + P(B) – P(A ∩ B) = 0.3 + 0.4 – 0.12 = 0.70 – 0.12 = 0.58 P (A|B) = (𝑃(𝐴 ∩ 𝐵))/(𝑃(𝐵)) = 0.12/0.40 = 12/40 = 0.3 P (B|A) = (𝑃(𝐴 ∩ 𝐵))/(𝑃(𝐴)) = (0. 12)/(0. 30) = 12/30 = 0.4

Ask a doubt
Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.