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Ex 13.1, 14 - Chapter 13 Class 12 Probability
Last updated at August 19, 2026 by Teachoo
Conditional Probability - Statement
Chapter 13 Class 12 Probability
Concept wise
- Conditional Probability - Values given
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Conditional Probability - Statement
- Multiplication rule of probability
- Independent events
- Basic Probability
- Theorem of total probability
- Bayes theorem
- Random Variable - Defination
- Probability distribution
- Mean or Expectation of random variable
- Variance and Standard Deviation of a Random Variable
- Bernoulli Trials
- Binomial Distribution
Transcript
Ex 13.1, 14 Given that the two numbers appearing on throwing two dice are different. Find the probability of the event ‘the sum of numbers on the dice is 4’.Two Dice are thrown We need to find the Probability that the sum of numbers on the dice is 4, given that the two numbers are different. E : Sum of numbers is 4 F : Numbers are different We need to find P(E|F) Also, E ∩ F = {(1, 3), (3, 1)} P(E ∩ F) = 2/36 = 1/18 Event E E = {(1, 3), (3, 1), (2, 2)} P(E) = 3/36 = 1/12 Event F P(F) = 30/36=5/6 Now, P(E|F) = (𝑃(𝐸 ∩ 𝐹))/(𝑃(𝐹)) = (2/36)/(30/36) = 2/30 = 𝟏/𝟏𝟓
