Ex 13.1, 9 - Mother, father, son line up at random for family - Ex 13.1

part 2 - Ex 13.1, 9 - Ex 13.1 - Serial order wise - Chapter 13 Class 12 Probability
part 3 - Ex 13.1, 9 - Ex 13.1 - Serial order wise - Chapter 13 Class 12 Probability

Take a fresh quiz. Then take another.
Every attempt is a new AI-adaptive Teachoo quiz with 5 questions, selected from your answers, mistakes, and progress.
Remove Ads

Transcript

Ex 13.1, 9 Mother, father and son line up at random for a family picture E : son on one end, F : father in middleMother, Father and son line up at random for a family picture So, Sample Space will be S = {(M, F, S), (M, S, F), (F, M, S), (F, S, M), (S, M, F), (S, F, M)} We need to find the probability that the son is on one end, given that the father is in the middle. So, E: Son on one end F: Father in middle We need to find P(E|F) Event E E = {(M,F,S), (F,M,S),(S,M,F), (S,F,M)} P(E) = 4/6=2/3 Event F F = {(M, F, S), (S, F, M)} P(F) = 2/6=1/3 Also, E ∩ F = {(M,F,S), (S,F,M)} ∴ P(E ∩ F) = 2/6=𝟏/𝟑 Now, P(E|F) = (𝑃(𝐸 ∩ 𝐹))/(𝑃(𝐹)) = (1/3)/(1/3) = 1

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.