Ex 2.1, 6 - Find principal value of tan-1 (-1) - Chapter 2 Inverse

Ex 2.1, 6 - Chapter 2 Class 12 Inverse Trigonometric Functions - Part 2

Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


Transcript

Ex 2.1, 6 (Method 1) Find the principal value of tan−1 (−1) Let y = tan−1 (−1) y = − tan−1 (1) y = − 𝝅/𝟒 Since Range of tan−1 is (−π/2,π/2) Hence, Principal Value of is (−𝝅)/𝟒 We know that tan−1 (−x) = − tan −1 x Since tan 𝜋/4 = 1 𝜋/4 = tan−1 (1) Ex 2.1, 6 (Method 2) Find the principal value of tan−1 (−1) Let y = tan−1 (−1) tan y = −1 tan y = tan ((−𝝅)/𝟒) Since Range of tan−1 is (−π/2,π/2) Hence, Principal Value of is (−𝝅)/𝟒 Rough We know that tan 45° = 1 θ = 45° = 45 × 𝜋/180 = 𝜋/4 Since −1 is negative Principal value is – θ i.e. (−𝜋)/4

Ask a doubt
Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.