Ex 2.1, 6 - Find principal value of tan-1 (-1) - Chapter 2 Inverse

Ex 2.1, 6 - Chapter 2 Class 12 Inverse Trigonometric Functions - Part 2

Something went wrong!

The video couldn't load due to a technical hiccup.
But don't worry — our team is already on it, and we're working hard to get it back up ASAP.

Thanks for bearing with us!

Share on WhatsApp

Transcript

Ex 2.1, 6 (Method 1) Find the principal value of tan−1 (−1) Let y = tan−1 (−1) y = − tan−1 (1) y = − 𝝅/𝟒 Since Range of tan−1 is (−π/2,π/2) Hence, Principal Value of is (−𝝅)/𝟒 We know that tan−1 (−x) = − tan −1 x Since tan 𝜋/4 = 1 𝜋/4 = tan−1 (1) Ex 2.1, 6 (Method 2) Find the principal value of tan−1 (−1) Let y = tan−1 (−1) tan y = −1 tan y = tan ((−𝝅)/𝟒) Since Range of tan−1 is (−π/2,π/2) Hence, Principal Value of is (−𝝅)/𝟒 Rough We know that tan 45° = 1 θ = 45° = 45 × 𝜋/180 = 𝜋/4 Since −1 is negative Principal value is – θ i.e. (−𝜋)/4

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo