Ex 2.1, 4 - Find principal value of tan-1 (- root 3) - CBSE

Ex 2.1, 4 - Chapter 2 Class 12 Inverse Trigonometric Functions - Part 2

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Ex 2.1, 4 (Method 1) Find the principal value of tan−1 (−√3) Let y = tan−1 (−√3) y = − tan−1 (√3) y = − 𝝅/𝟑 Since Range of tan−1 is ((−π)/2 "," π/2) Hence, Principal Value is (−𝝅)/𝟑 We know that tan−1 (−x) = − tan −1 x Since tan 𝜋/3 = √3 𝜋/3 = tan−1 (√3) Ex 2.1, 4 (Method 2) Find the principal value of tan−1 (−√3) Let y = tan−1 (−√3) tan y = −√3 tan y = tan ((−𝝅)/𝟑) Since Range of tan−1 is ((−π)/2 "," π/2) Hence, Principal Value is (−𝝅)/𝟑 Rough We know that tan 60° = √3 θ = 60° = 60° × 𝜋/180 = 𝜋/3 Since −√3 is negative Principal value is −θ i.e. (−𝜋)/3

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.