Question 15 — The species 27Al, 80Br– and - Questions at the end of the chapter - Chapter 9 - Atomic Foundations of Matter (Exploration)

Last updated at July 20, 2026 by

Question 15
The species ²⁷Al, ⁸⁰Br⁻ and ²⁰¹Hg²⁺ have 13, 35 and 80 protons, respectively. How many electrons and neutrons do they have?
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  • ²⁷Al (neutral): electrons = 13; neutrons = 27 − 13 = 14 .
  • ⁸⁰Br⁻ (gained 1 e): electrons = 35 + 1 = 36 ; neutrons = 80 − 35 = 45 .
  • ²⁰¹Hg²⁺ (lost 2 e): electrons = 80 − 2 = 78 ; neutrons = 201 − 80 = 121 .
Electrons and Neutrons Al: 13 electrons, 14 neutrons Br minus: 36 electrons, 45 neutrons Hg 2 plus: 78 electrons, 121 neutrons
Back to: 9.4.2 Bonding by electron transfer — Ionic bond
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