Question 1
A particular element (A) has one electron in its third shell. There is another element (B) with six electrons in its second shell. (i) How many electrons does A tend to give or take to become stable? (ii) What kind of ion would it form? (iii) How many electrons does B tend to give or take to become stable? (iv) What kind of ion would it form? (v) If A and B were to combine, what kind of bond would be formed? (vi) What would be the formula for the compound thus formed?
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  • A is 2, 8, 1 (like sodium): (i) gives 1 electron; (ii) forms a cation A⁺ .
  • B is 2, 6 (like oxygen): (iii) takes 2 electrons; (iv) forms an anion B²⁻ .
  • (v) A gives electrons and B takes them → an ionic bond .
  • (vi) Two A⁺ balance one B²⁻ → formula A₂B .
Ionic Compound from A and B A (2,8,1) gives 1 electron B (2,6) takes 2 electrons Formula A2B, an ionic bond
Back to: 9.4.2 Bonding by electron transfer — Ionic bond
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