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Question 2 - Think & Reflect (Page 185) Let us revisit the sequence 𝑑_n of triangular numbers 1, 3, 6, 10, 15,… shown in Fig. 8.1. Note that the 𝑛^"th " term of this sequence is the sum of the first 𝑛 natural numbers. Thus 𝑑_𝑛=(𝑛(𝑛+1))/2. Can you use this to find the 10^"th " ,17^"th " and 80^"th " triangular numbers? A triangular number is literally just the sum of the first n natural numbers. Like 4th Triangular number = 1 + 2 + 3 + 4 = 10 Thus, we can write nth Triangular number = 𝒕_𝒏=(𝒏(𝒏 + 𝟏))/𝟐 Finding 10th, 17th and 80th triangular number now 10th triangular number = 𝑑_10 = (𝟏𝟎 Γ— 𝟏𝟏)/𝟐 = 5 Γ— 11 = 55 17th triangular number = 𝑑_17 = (πŸπŸ• Γ— πŸπŸ–)/𝟐 = 17 Γ— 9 = 153 80th triangular number = 𝑑_80 = (πŸ–πŸŽ Γ— πŸ–πŸ)/𝟐 = 40 Γ— 81 = 3240

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