Let us revisit the sequence tn of triangular numbers 1, 3, 6, 10, 15 - Sum of the First n Natural Numbers

part 2 - Question 2 - Think & Reflect (Page 185) - Sum of the First n Natural Numbers - Chapter 8 - Predicting What Comes Next: Exploring Sequences & Progress - Maths Class 9
part 3 - Question 2 - Think & Reflect (Page 185) - Sum of the First n Natural Numbers - Chapter 8 - Predicting What Comes Next: Exploring Sequences & Progress - Maths Class 9

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Question 2 - Think & Reflect (Page 185) Let us revisit the sequence ๐‘ก_n of triangular numbers 1, 3, 6, 10, 15,โ€ฆ shown in Fig. 8.1. Note that the ๐‘›^"th " term of this sequence is the sum of the first ๐‘› natural numbers. Thus ๐‘ก_๐‘›=(๐‘›(๐‘›+1))/2. Can you use this to find the 10^"th " ,17^"th " and 80^"th " triangular numbers? A triangular number is literally just the sum of the first n natural numbers. Like 4th Triangular number = 1 + 2 + 3 + 4 = 10 Thus, we can write nth Triangular number = ๐’•_๐’=(๐’(๐’ + ๐Ÿ))/๐Ÿ Finding 10th, 17th and 80th triangular number now 10th triangular number = ๐‘ก_10 = (๐Ÿ๐ŸŽ ร— ๐Ÿ๐Ÿ)/๐Ÿ = 5 ร— 11 = 55 17th triangular number = ๐‘ก_17 = (๐Ÿ๐Ÿ• ร— ๐Ÿ๐Ÿ–)/๐Ÿ = 17 ร— 9 = 153 80th triangular number = ๐‘ก_80 = (๐Ÿ–๐ŸŽ ร— ๐Ÿ–๐Ÿ)/๐Ÿ = 40 ร— 81 = 3240

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