Sum of the First n Natural Numbers
Last updated at June 9, 2026 by Teachoo
Transcript
Question 2 - Think & Reflect (Page 185) Let us revisit the sequence π‘_n of triangular numbers 1, 3, 6, 10, 15,β¦ shown in Fig. 8.1. Note that the π^"th " term of this sequence is the sum of the first π natural numbers. Thus π‘_π=(π(π+1))/2. Can you use this to find the 10^"th " ,17^"th " and 80^"th " triangular numbers? A triangular number is literally just the sum of the first n natural numbers. Like 4th Triangular number = 1 + 2 + 3 + 4 = 10 Thus, we can write nth Triangular number = π_π=(π(π + π))/π Finding 10th, 17th and 80th triangular number now 10th triangular number = π‘_10 = (ππ Γ ππ)/π = 5 Γ 11 = 55 17th triangular number = π‘_17 = (ππ Γ ππ)/π = 17 Γ 9 = 153 80th triangular number = π‘_80 = (ππ Γ ππ)/π = 40 Γ 81 = 3240