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Example 4 Find the first four terms of the sequence given by the recursive rule 𝑠_1=3,𝑠_𝑛=𝑠_(π‘›βˆ’1) (𝑠_(π‘›βˆ’1)βˆ’1) for 𝑛β‰₯2. First, let’s find first four terms i.e. 𝒔_𝟏, 𝒔_𝟐, 𝒔_πŸ‘, 𝒔_πŸ’ Given First term = 𝒔_𝟏 = 3 Second term = 𝑠_2 = 𝑠_(2βˆ’1) (𝑠_(2βˆ’1)βˆ’1) = 𝒔_𝟏 (𝒔_πŸβˆ’πŸ) = 3 Γ— (3 – 1) = 3 Γ— 2 = 6 Third term = 𝑠_3 = 𝑠_(3βˆ’1) (𝑠_(3βˆ’1)βˆ’1) = 𝒔_𝟐 (𝒔_πŸβˆ’πŸ) = 6 Γ— (6 – 1) = 6 Γ— 5 = 30 Fourth term = 𝑠_4 = 𝑠_(4βˆ’1) (𝑠_(4βˆ’1)βˆ’1) = 𝒔_πŸ‘ (𝒔_πŸ‘βˆ’πŸ) = 30 Γ— (30 – 1) = 30 Γ— 29 = 870 Thus, first four terms of the sequence are 3, 6, 30, 870

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