Recursive Rule for a Sequence
Recursive Rule for a Sequence
Last updated at June 9, 2026 by Teachoo
Transcript
Example 4 Find the first four terms of the sequence given by the recursive rule π _1=3,π _π=π _(πβ1) (π _(πβ1)β1) for πβ₯2. First, letβs find first four terms i.e. π_π, π_π, π_π, π_π Given First term = π_π = 3 Second term = π _2 = π _(2β1) (π _(2β1)β1) = π_π (π_πβπ) = 3 Γ (3 β 1) = 3 Γ 2 = 6 Third term = π _3 = π _(3β1) (π _(3β1)β1) = π_π (π_πβπ) = 6 Γ (6 β 1) = 6 Γ 5 = 30 Fourth term = π _4 = π _(4β1) (π _(4β1)β1) = π_π (π_πβπ) = 30 Γ (30 β 1) = 30 Γ 29 = 870 Thus, first four terms of the sequence are 3, 6, 30, 870