Mean when a Number is Added to each term [Class 8 Ganita Prakash II] - Tinkering with Mean

part 2 - Mean when a Number is Added to each term - Tinkering with Mean - Chapter 5 Class 8 - Tales by Dots and Lines (Ganita Prakash II) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
part 3 - Mean when a Number is Added to each term - Tinkering with Mean - Chapter 5 Class 8 - Tales by Dots and Lines (Ganita Prakash II) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT) part 4 - Mean when a Number is Added to each term - Tinkering with Mean - Chapter 5 Class 8 - Tales by Dots and Lines (Ganita Prakash II) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT) part 5 - Mean when a Number is Added to each term - Tinkering with Mean - Chapter 5 Class 8 - Tales by Dots and Lines (Ganita Prakash II) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)

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Mean when a Number is Added to each termLet’s Consider the data: 8, 3, 10, 13, 4, 6, 7, 7, 8, 8, 5. Finding its mean Now, Mean = (π‘†π‘’π‘š π‘œπ‘“ π‘Žπ‘™π‘™ π‘‘π‘’π‘Ÿπ‘šπ‘ )/(π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘‘π‘’π‘Ÿπ‘šπ‘ ) = (8 + 3 + 10 + 13 + 4 + 6 + 7 + 7 + 8 + 8 + 5)/11 = 79/11 = 7.18 (approx.) Now, let’s add each term with 10 So, our new data becomes 18, 13, 20, 23, 14, 16, 17, 17, 18, 18, 15 Now, New Mean = (π‘†π‘’π‘š π‘œπ‘“ π‘Žπ‘™π‘™ π‘‘π‘’π‘Ÿπ‘šπ‘ )/(π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘‘π‘’π‘Ÿπ‘šπ‘ ) = (18 +13 +20 +23 +14 +16 +17 +17 +18 +18 +15)/11 = 189/11 = 17.18 (approx.) We ntocie that New Mean = Old mean + 10 Checking on a dot plot Let’s try to prove it generally General Statement Let the original values be π‘₯_1,π‘₯_2,…,π‘₯_𝑛 and their average be π‘Ž. 𝒂=(𝒙_𝟏 + 𝒙_𝟐 + β‹― + 𝒙_𝒏)/𝒏 If we subtract 2 from every value, the new average calculation looks like this: " New Average "=((π‘₯_1βˆ’2) + (π‘₯_2βˆ’2) + β‹― + (π‘₯_π‘›βˆ’2))/𝑛 We can group all the π‘₯ terms together, and count how many times we subtracted 2 (which is 𝑛 times): =((π‘₯_1 + π‘₯_2 + β‹― + π‘₯_𝑛 )βˆ’2𝑛)/𝑛 =(π‘₯_1 + π‘₯_2 + β‹― + π‘₯_𝑛)/π‘›βˆ’2𝑛/𝑛 =(π‘₯_1 + π‘₯_2 + β‹― + π‘₯_𝑛)/π‘›βˆ’2 Substitute our original average 𝒂 back in, and cancel the 𝑛 s in the second term: =π’‚βˆ’πŸ Thus, we can write If number a is added to each term New Mean = Old mean + a If number b is subtracted to each term New Mean = Old mean – b

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CA Maninder Singh

CA Maninder Singh is a Chartered Accountant for the past 16 years. He also provides Accounts Tax GST Training in Delhi, Kerala and online.