Last updated at March 5, 2026 by Teachoo
Transcript
Mean when a Number is Added to each termLetβs Consider the data: 8, 3, 10, 13, 4, 6, 7, 7, 8, 8, 5. Finding its mean Now, Mean = (ππ’π ππ πππ π‘ππππ )/(ππ’ππππ ππ π‘ππππ ) = (8 + 3 + 10 + 13 + 4 + 6 + 7 + 7 + 8 + 8 + 5)/11 = 79/11 = 7.18 (approx.) Now, letβs add each term with 10 So, our new data becomes 18, 13, 20, 23, 14, 16, 17, 17, 18, 18, 15 Now, New Mean = (ππ’π ππ πππ π‘ππππ )/(ππ’ππππ ππ π‘ππππ ) = (18 +13 +20 +23 +14 +16 +17 +17 +18 +18 +15)/11 = 189/11 = 17.18 (approx.) We ntocie that New Mean = Old mean + 10 Checking on a dot plot Letβs try to prove it generally General Statement Let the original values be π₯_1,π₯_2,β¦,π₯_π and their average be π. π=(π_π + π_π + β― + π_π)/π If we subtract 2 from every value, the new average calculation looks like this: " New Average "=((π₯_1β2) + (π₯_2β2) + β― + (π₯_πβ2))/π We can group all the π₯ terms together, and count how many times we subtracted 2 (which is π times): =((π₯_1 + π₯_2 + β― + π₯_π )β2π)/π =(π₯_1 + π₯_2 + β― + π₯_π)/πβ2π/π =(π₯_1 + π₯_2 + β― + π₯_π)/πβ2 Substitute our original average π back in, and cancel the π s in the second term: =πβπ Thus, we can write If number a is added to each term New Mean = Old mean + a If number b is subtracted to each term New Mean = Old mean β b