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Constructing Angle Bisectors
Last updated at February 6, 2026 by Teachoo
Constructing Angle Bisectors
Class 7 (Ganita Prakash 1, 2 & old NCERT)
Chapter 6 Class 7 - Constructions and Tilings (Ganita Prakash II)
- Constructing an Eye
- Constructing a Perpendicular Bisector
- Constructing angle 90°
- Construction Methods in Śulba-Sūtras
-
Constructing Angle Bisectors
- Figure it out - Pag 144, 145
- Constructing Copy of an Angle
- Construction of a Line Parallel to the Given Line
- Constructing Arch Designs
- Constructing Regular Hexagon, Angle 60° and 6-pointed Star
- Figure it out - Pag 154, 155
- Tangrams
- Tiling
- Figure it out - Page 160
- Tiling the Entire Plane
Transcript
Constructing Angle BisectorsFor any angle, Angle bisector divides it into 2 equal parts Here, a = (∠ 𝑨𝑩𝑪)/𝟐 Let’s say Given an angle ABC, we want to construct is bisector Steps of Construction: 1. Draw an arc of any radius intersecting BA and BC at points E & D 2. Next, taking D and E as centers and with the radius more than 1/2 DE, draw arcs to intersect each other. 3. Mark the point as F. 4. Join BF So, BF is the bisector of the ∠ ABC.
