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Question 2 - Figure it out - Page 39 - Chapter 2 Class 7 - Operations with Integers (Ganita Prakash II)
Last updated at January 21, 2026 by Teachoo
Class 7 (Ganita Prakash 1, 2 & old NCERT)
Chapter 2 Class 7 - Operations with Integers (Ganita Prakash II)
- Quick Recap on Intergers
- Carrom Coin Integers
- Token Model for Adding and Subtracting Integers
- Multiplication of Integers
- Patterns in Integer Multiplication
- Brahmagupta’s Rules for Multiplication and Division of Integers
- A Magic Grid of Integers
- Division of Integers
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Figure it out - Page 39
- Integer Expressions - Properties and Pattern
- Figure it out - Page 42, 43, 44
Transcript
Question 2 - Page 173 A freezing process requires that the room temperature be lowered from 32°C at the rate of 5°C every hour. What will be the room temperature 10 hours after the process begins?Initial Temperature = 32°C Temperature decreases at 5°C per hour We need to find Temperature after 10 hours Now, Decrease in temperature in 1 hour = 5° C Decrease in temperature in 10 hours = 5 × 10 = 50° C Thus, Temperature after 10 hours = Initial Temperature – Decrease in Temperature = 32° C – 50° C = 32 – 50 = –50 + 32 = – (50 – 32) = –18° C Thus, final temperature is –18° C
