Question 1 - Figure it out - Page 39 - Chapter 2 Class 7 - Operations with Integers (Ganita Prakash II)

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[Class 7 Part 2] Find the values of: (a) 14 × (– 15) - Ganita Prakash - Figure it out - Page 39

part 2 - Question 1 - Figure it out - Page 39 - Chapter 2 Class 7 - Operations with Integers (Ganita Prakash II) - Class 7 (Ganita Prakash 1, 2 & old NCERT)
part 3 - Question 1 - Figure it out - Page 39 - Chapter 2 Class 7 - Operations with Integers (Ganita Prakash II) - Class 7 (Ganita Prakash 1, 2 & old NCERT) part 4 - Question 1 - Figure it out - Page 39 - Chapter 2 Class 7 - Operations with Integers (Ganita Prakash II) - Class 7 (Ganita Prakash 1, 2 & old NCERT)

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Question 1 - Page 173 Find the values of: (a) 14 × (– 15)Since there is one negative sign, answer is negative Thus, 14 × (–15) = –210 Question 1 - Page 173 Find the values of: (b) – 16 × (– 5)Since there are two negative signs, answer is positive Thus, (–16) × (–5) = 16 × 5 = 80 Question 1 - Page 173 Find the values of: (c) 36 ÷ (– 18)Since there is one negative sign, answer is negative Now, 36 ÷ (– 18) = 36/(−18) = (−36)/18 = –2 Question 1 - Page 173 Find the values of: (d) (– 46) ÷ (– 23)Since there are two negative signs, answer is positive Now, (–46) ÷ (– 23) = (−46)/(−23) = 46/23 = 2

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