Question 11 - Figure it out - Page 42, 43, 44 - Chapter 2 Class 7 - Operations with Integers (Ganita Prakash II)

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Question 11 Find the values of: (a) (32 × (– 18)) ÷ ((– 36))Now, (32 × (– 18)) ÷ ((– 36)) = (𝟑𝟐 × −𝟏𝟖)/(−𝟑𝟔) Both negative signs cancel as one is in numerator, other in denominator = (32 × 18)/36 = (32 × 3)/6 = (32 × 1)/2 = 16 Question 11 Find the values of: (b) (32 ) ÷ ((– 36) × (– 18))Now, (32 ) ÷ ((– 36) × (– 18)) = 𝟑𝟐/(−𝟑𝟔 × −𝟏𝟖) = 32/(36 × 18) = 8/(9 × 18) = 4/(9 × 9) = 𝟒/𝟖𝟏 Question 11 Find the values of: (c) (25 × (– 12)) ÷ ((45) × (– 27))Now, (25 × (– 12)) ÷ ((45) × (– 27)) = (𝟐𝟓 × −𝟏𝟐)/(𝟒𝟓 × −𝟐𝟕) Both negative signs cancel as one is in numerator, other in denominator = (25 × 12)/(45 × 27) = (5 × 12)/(9 × 27) = (5 × 4)/(3 × 27) = 𝟐𝟎/𝟖𝟏 Question 11 Find the values of: (d) (280 × (– 7)) ÷ ((– 8) × (– 35))Now, (280 × (– 7)) ÷ ((– 8) × (– 35)) = (𝟐𝟖𝟎 × −𝟕)/(−𝟖 × −𝟑𝟓) = (−280 × 7)/(8 × 35) = (−280 × 1)/(8 × 5) = (−𝟐𝟖𝟎)/𝟒𝟎 = (−28)/4 = –7