Question 9 - Figure it out - Page 42, 43, 44 - Chapter 2 Class 7 - Operations with Integers (Ganita Prakash II)

Transcript

Question 9 Find 3 consecutive numbers with a product of (a) – 6, (b) 120.(a) For Product –6 Since Product is negative, and we are multiplying 3 numbers (odd numbers) All numbers would be negative Thus, we write –6 as product of –1, –2, –3 Therefore, –6 = –1 × –2 × –3 Answer is –1, –2, –3 (b) For Product 120 Since Product is positive, and we are multiplying 3 numbers (odd numbers) All numbers would be positive Now, for 120 We need 0, so we can do 9, 10, 11 – but this is too big So, we do 4, 5, 6 – this works Thus, we write 120 as product of 4, 5, 6 Therefore, 120 = 4 × 5 × 6 Answer is 4, 5, 6