![[Class 7] Find pairs of numbers from their Sum = –7, Difference = –13 - Quick Recap on Intergers](https://cdn.teachoo.com/ca4667b0-c292-46fe-a5ce-c0e179255758/slide17.jpg)
Question (f) - Page 25 (Figure it out) - Quick Recap on Intergers - Chapter 2 Class 7 - Operations with Integers (Ganita Prakash II)
Last updated at January 21, 2026 by Teachoo
Quick Recap on Intergers
Integers - Quick Revision
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Class 7 (Ganita Prakash 1, 2 & old NCERT)
Chapter 2 Class 7 - Operations with Integers (Ganita Prakash II)
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Quick Recap on Intergers
- Carrom Coin Integers
- Token Model for Adding and Subtracting Integers
- Multiplication of Integers
- Patterns in Integer Multiplication
- Brahmagupta’s Rules for Multiplication and Division of Integers
- A Magic Grid of Integers
- Division of Integers
- Figure it out - Page 39
- Integer Expressions - Properties and Pattern
- Figure it out - Page 42, 43, 44
Transcript
Question (f) - Page 25 (Figure it out) Let us try to find a few more pairs of numbers from their sums and differences: (f) Sum = –7, Difference = –13 Guessing this would be very time consuming We can do this by Algebra Since we need to find two numbers, We can write the situation as 1st Number + 2nd Number = –7 1st Number – 2nd Number = –13 Adding (1) & (2) (1st Number + 2nd Number) + (1st Number – 2nd Number) = –7 – 13 2 × 1st Number = – (7 + 13) 2 × 1st Number = – 20 1st Number = (−20)/2 1st Number = –10 Now, putting value in (1) 1st Number + 2nd Number = –7 –10 + 2nd Number = –7 2nd Number = –7 + 10 2nd Number = 10 – 7 2nd Number = 3 Thus, the two numbers are –10 and 3
