Question (vii) - Digits in Disguise - Chapter 5 Class 8 - Number Play (Ganita Prakash)

Transcript

Question (vii) Here is one more: BYE × 6 = RAY.Here, a 3-digit number multiplied by a 1-digit number gives another 3-digit number If B = 2 We can take any number here, say 201 Then, 201 × 6 = 1206 Which is a 4-digit number Thus, B = 1 So, our equation beomces 1YE × 6 = RAY Now, for Y If Y = 7 We can take any number here, say 170 Then, 170 × 6 = 1020 Which is a 4-digit number Thus, Y is always less than 7 Let’s assume Y = 0 Our equation is now 10E × 6 = RA0 Now, RAO ends with 0. It is possible only if we multiply 105 × 6 = 630 Checking if it matches with BYE × 6 = RAY Here, all digits are different Thus, our answer is B = 1, Y = 0, E = 5, R = 6, A = 3 Note: We have to put multiple values of Y to achieve the answer, usually we start with the simplest option