[Ganita Prakash] Cryptarithms: AB + 37 = 6A - (Number Play)  - Teachoo - Digits in Disguise

part 2 - Question (ii) - Digits in Disguise - Chapter 5 Class 8 - Number Play (Ganita Prakash) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
part 3 - Question (ii) - Digits in Disguise - Chapter 5 Class 8 - Number Play (Ganita Prakash) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)

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Question (ii) – Page 131 Step 1 - Checking unit digit 𝐡+7 ends in 𝐴. Step 2 - Checking Ten’s Digit 𝐴+3 equals 6 . This suggests 𝐴 is probably 2 or 3 . Trial 1 – If A = 3: If 𝐴=3, then πŸ‘π‘©+πŸ‘πŸ•=πŸ”πŸ‘ 3B=63βˆ’37 πŸ‘π=πŸπŸ” First digit don’t match, as 3 β‰  2 So, it is not possible Trial 2 – If A = 2: If 𝐴=2, then πŸπ‘©+πŸ‘πŸ•=πŸ”πŸ 2B=62βˆ’37 𝟐𝐁=πŸπŸ“ So, B = 5 Check: 25+37=62 This is true Thus, 𝐀=𝟐," " 𝐁=πŸ“

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CA Maninder Singh

CA Maninder Singh is a Chartered Accountant for the past 16 years. He also provides Accounts Tax GST Training in Delhi, Kerala and online.