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Question (vi) - Digits in Disguise - Chapter 5 Class 8 - Number Play (Ganita Prakash)
Last updated at January 8, 2026 by Teachoo
Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
Chapter 5 Class 8 - Number Play (Ganita Prakash)
- Sum of Consecutive Numbers
- Parity of Arithmetic & Algebraic Expressions
- Pairs to Make Fours
- Factors and Multiples
- Always, Sometimes, or Never
- What Remains?
- Figure it out - Page 122, 123
- Divisibility Rules - 2, 5, 10 and 3
- Shortcut for Divisibility by 9
- Figure it out - Page 126
- Shortcut for Divisibility by 11
- Divisibility Shortcuts for Other Numbers
- Digital Roots
- Figure it out - Page 131
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Digits in Disguise
- Figure it out - Page 132, 133, 134
Transcript
Question (vi) – Page 131 Try this now: GH × H = 9K.Here, a 2-digit number multiplied by a 1-digit number gives another 2-digit number in the 90s We can do this by finding different multiplications to make number in 90s. Like 11 × 9 = 99, but it doesn’t follow GH × H. So, not possible 12 × 8 = 96, but it doesn’t follow GH × H. So, not possible 46 × 2 = 92, but it doesn’t follow GH × H. So, not possible 47 × 2 = 94, but it doesn’t follow GH × H. So, not possible 24 × 4 = 96, this follows GH × H = 9K. So, it is possible 31 × 3 = 93, but it doesn’t follow GH × H. So, not possible 16 × 6 = 96 , but it doesn’t follow GH × H = 9K as H ≠ K. So, not possible Thus, our equation is 24 × 4 = 96 And, our answer is G = 2, H = 4, K = 6
