[Number Play] Cryptarithms: QR + QR + QR = PRR - Ganita Prakash - Digits in Disguise

part 2 - Question (iv) - Digits in Disguise - Chapter 5 Class 8 - Number Play (Ganita Prakash) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
part 3 - Question (iv) - Digits in Disguise - Chapter 5 Class 8 - Number Play (Ganita Prakash) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)

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Transcript

Question (iv) – Page 131 This is the same as writing 𝑄𝑅 Γ— 3=𝑃𝑅𝑅 Now, 3 Γ— 𝑅 ends in 𝑅. This only happens if 𝐑=𝟎 or 𝐑=πŸ“. Let’s try both If 𝑹=𝟎: 𝑄0Γ—3=𝑃00 This is impossible, as no value of Q will give two zero’s at the end If 𝑹=πŸ“: Units Column 3 Γ— 5=15 (carry 1 ). Tens column: (3 Γ— 𝑄)+1 must end in 𝑅 (which is 5). So, 3 Γ— 𝑄 must end in 4. Thus, Q can be 8 as 3 Γ— 8=24 Check: πŸ–πŸ“ Γ— πŸ‘=πŸπŸ“πŸ“ Thus, our answer is 𝐐=πŸ–,𝐑=πŸ“,𝐏=𝟐

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CA Maninder Singh is a Chartered Accountant for the past 16 years. He also provides Accounts Tax GST Training in Delhi, Kerala and online.