Question (iii) - Digits in Disguise - Chapter 5 Class 8 - Number Play (Ganita Prakash)

Last updated at January 8, 2026 by

[Class 8] Cryptarithms: ON + ON + ON = PO - [Ganita Prakash] - Digits in Disguise

part 2 - Question (iii) - Digits in Disguise - Chapter 5 Class 8 - Number Play (Ganita Prakash) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)

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Question (iii) – Page 131 This is the same as saying 𝑂𝑁 Γ— 3=𝑃𝑂. Now, 𝑁 multiplied by 3 ends in 𝑂. 𝑂 multiplied by 3 (plus carry) equals 𝑃 𝑷𝑢 is a two digit number, with maximum value 99 So, ON has maximum value 33 Let’s try O = 1 Then, our equation becomes 1N Γ— 3 = P1 Since N Γ— 3 ends with 1, N = 7 For N = 7 17 Γ— 3 = 51 So, P = 5 Thus, our answer is 𝐎=𝟏," " 𝐍=πŸ•,𝐏=πŸ“

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