Finding Sum using Abacus

Transcript

Finding Sum using Abacus Let us consider a simple addition problem: 2907 + 43. The two numbers were taken on either side of the vertical partition. We arrange the beads - Starting from 1, then 10, then 100, then 1000 A vertical line separates the board into two sides. Left Side: Represents 2907 Right Side: Represents 𝟒𝟑 Let's analyze the setup in the picture: Left Side (2907): 1000s: 2 beads on line (2000). 100" " s:1 above (500)+4 on line (400)=900. 10s: Empty (0). 1s: 1 above (5)+2 on line (2)=7. Right Side (43): 10s: 4 beads on line (40). 1s: 3 beads on line (3). How to find the Sum To add, you "slide" the beads from the right side over to join the beads on the left side. Step 1: The Ones (1s) You have 𝟕 on the left and 𝟑 on the right. 7+3=10. Rule: You cannot have 10 ones! Action: Remove all the beads from the 1s line and place 𝟏 bead on the 𝟏𝟎 s line. (This is "Carrying over"). Step 2: The Tens (10s) The Left side was empty (0). The Right side had 4. Plus the 𝟏 we just carried over from the ones place. 0+4+1=𝟓. Action: Place 1 bead floating above the 10 s line (because floating = 5). Step 3: The Hundreds (100s) & Thousands (1000s) There is nothing on the right side to add. Keep the 𝟗𝟎𝟎 and 2000 exactly as they are. Final Answer: 2 on the 1000 s line. 9 on the 100 s line. 5 on the 10 s line. 0 on the 1 s line. Result: 2950