[Class 6] Constructing a rectangle divided into 3 identical squares. - Construct Breaking Rectangles

part 2 - Constructing a rectangle divided into 3 identical squares. - Construct Breaking Rectangles - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT)
part 3 - Constructing a rectangle divided into 3 identical squares. - Construct Breaking Rectangles - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 4 - Constructing a rectangle divided into 3 identical squares. - Construct Breaking Rectangles - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 5 - Constructing a rectangle divided into 3 identical squares. - Construct Breaking Rectangles - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 6 - Constructing a rectangle divided into 3 identical squares. - Construct Breaking Rectangles - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 7 - Constructing a rectangle divided into 3 identical squares. - Construct Breaking Rectangles - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 8 - Constructing a rectangle divided into 3 identical squares. - Construct Breaking Rectangles - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 9 - Constructing a rectangle divided into 3 identical squares. - Construct Breaking Rectangles - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT)

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Transcript

Constructing a rectangle divided into 3 identical squares.We need to construct this Now, let’s do steps- of construction Since all angles are 90° ∴ ∠ A = ∠ B = ∠ C = ∠ D = 90° We draw the rectangle using 2 sides, and 3 angles Steps of construction 1. Draw side AB of length 12 cm 2. Now, we draw 90° from point A 3. Now, we draw 90° from point B Taking 4 cm as radius, and B as center, draw an arc. Where the arc intersects the line is point C Now, make 90° from point C 6. Mark point D where the lines from point A and point C intersect 7. Now keeping compass as same 4 cm open, draw an arc from point A on AB – marking point AB 8. Similarly, keep pointy end on E, compass same 4 cm open and mark point F To mark H and G – we can use two methods Method 1 – Make 90° from point E and point F and intersect line CD at point H and G respectively Method 2 – Mark 4 cm from point D to mark point H and 4 cm from point G to mark point G 9. Using Method 2 to make points H and G 10. Join EH and FG Thus, this is our required figure

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