[Class 6] Constructing a rectangle divided into 3 identical squares. - Construct Breaking Rectangles

part 2 - Constructing a rectangle divided into 3 identical squares. - Construct Breaking Rectangles - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT)
part 3 - Constructing a rectangle divided into 3 identical squares. - Construct Breaking Rectangles - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT)
part 4 - Constructing a rectangle divided into 3 identical squares. - Construct Breaking Rectangles - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT)
part 5 - Constructing a rectangle divided into 3 identical squares. - Construct Breaking Rectangles - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 6 - Constructing a rectangle divided into 3 identical squares. - Construct Breaking Rectangles - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 7 - Constructing a rectangle divided into 3 identical squares. - Construct Breaking Rectangles - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 8 - Constructing a rectangle divided into 3 identical squares. - Construct Breaking Rectangles - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 9 - Constructing a rectangle divided into 3 identical squares. - Construct Breaking Rectangles - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT)

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Transcript

Constructing a rectangle divided into 3 identical squares.We need to construct this Now, let’s do steps- of construction Since all angles are 90° ∴ ∠ A = ∠ B = ∠ C = ∠ D = 90° We draw the rectangle using 2 sides, and 3 angles Steps of construction 1. Draw side AB of length 12 cm 2. Now, we draw 90° from point A 3. Now, we draw 90° from point B Taking 4 cm as radius, and B as center, draw an arc. Where the arc intersects the line is point C Now, make 90° from point C 6. Mark point D where the lines from point A and point C intersect 7. Now keeping compass as same 4 cm open, draw an arc from point A on AB – marking point AB 8. Similarly, keep pointy end on E, compass same 4 cm open and mark point F To mark H and G – we can use two methods Method 1 – Make 90° from point E and point F and intersect line CD at point H and G respectively Method 2 – Mark 4 cm from point D to mark point H and 4 cm from point G to mark point G 9. Using Method 2 to make points H and G 10. Join EH and FG Thus, this is our required figure

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo