Question 2 (b) - Figure it out - Page 182 - Chapter 7 Class 6 - Fractions (Ganita Prakash)

Last updated at July 21, 2026 by

[Maths Class 6] Subtract as indicated: 18/5 from 23/3 - Figure it out - Figure it out - Page 182

part 2 - Question 2 (b) - Figure it out - Page 182 - Chapter 7 Class 6 - Fractions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT)

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Transcript

Question 2 (b) Subtract as indicated: b. 18/5 from 23/3 Basically we have to do šŸšŸ‘/šŸ‘āˆ’šŸšŸ–/šŸ“ We make denominator same by multiplying both denominators 3 Ɨ 5 = 15 So, our fractions become šŸšŸ‘/šŸ‘=23/3 Ɨ5/5 =šŸšŸšŸ“/šŸšŸ“ šŸšŸ–/šŸ“=18/5 Ɨ3/3 =šŸ“šŸ’/šŸšŸ“ Now, our subtraction becomes 23/3āˆ’18/5 = 115/15āˆ’54/15 = (115 āˆ’ 54)/15 = šŸ”šŸ/šŸšŸ“

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