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Puzzle time Question - Page 62
Last updated at June 18, 2025 by Teachoo
Class 6 (Ganit Prakash)
Chapter 3 Class 6 - Number Play (Ganita Prakash)
- Numbers can Tell us Things, Supercells,
- Supercells
- Supercells in a grid (Page 58)
- Patterns of Numbers on the Number Line, Playing with Digits
- Playing with Digits
-
Pretty Palindromic Patterns
- The Magic Number of Kaprekar
- Clock and Calendar Numbers
- Figure it out - Page 64, 65
- Mental Math
- Playing with Number Patterns, and Collatz Conjecture!
- Simple Estimation
- Estimate the answer - Page 70, 71
- Games and Winning Strategies
- Figure it out - Page 72, 73
Transcript
Puzzle time Question - Page 62 I am a 5-digit palindrome. I am an odd number. My ‘t’ digit is double of my ‘u’ digit. My ‘h’ digit is double of my ‘t’ digit. Who am I? Let’s answer it I am an odd number: This means the last digit ('u') must be odd (1, 3, 5, 7, or 9). My 't' digit is double of my 'u' digit: If the 'u' digit were 3, the 't' digit would be 6. But then ‘h’ is double of ‘t’, so it cannot be 12 - which is not a single digit If the 'u' digit were 5 or higher, the 't' digit would be 10 or more, which isn't a single digit. This leaves the 'u' digit as 1 and the 't' digit as 2. My 'h' digit is double of my 't' digit: Since the 't' digit is 2, the 'h' digit must be 4 (2 × 2). I am a 5-digit palindrome: A palindrome reads the same forwards and backwards. Since the first three digits are 1, 2, and 4, the number must be 12,421. Hence, Who am I? 12,421 Write the number in words: Twelve thousand, four hundred twenty-one
