Ex 8.1, 12 - Write five terms series a1 = -1, an = an-1/n - Ex 8.1

part 2 - Ex 8.1, 12 - Ex 8.1 - Serial order wise - Chapter 8 Class 11 Sequences and Series
part 3 - Ex 8.1, 12 - Ex 8.1 - Serial order wise - Chapter 8 Class 11 Sequences and Series part 4 - Ex 8.1, 12 - Ex 8.1 - Serial order wise - Chapter 8 Class 11 Sequences and Series part 5 - Ex 8.1, 12 - Ex 8.1 - Serial order wise - Chapter 8 Class 11 Sequences and Series

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Ex9.1 , 12 Write the first five terms of the following sequence and obtain the corresponding series: a1 = -1 , an = š‘Ž_(š‘›āˆ’1)/š‘› , n ≄ 2 It is given that a1 = -1, For a2 and onward, we have to use this formula an = š‘Ž_(š‘›āˆ’1)/š‘› Putting n = 2 in (1) a2 = š‘Ž_(2āˆ’1)/2 = š‘Ž_1/2 = (āˆ’1)/2 Putting n = 3 in (1) a3 = š‘Ž_(3 āˆ’ 1 )/3 a3 = (a2āˆ’)/3 a3 = ((āˆ’1)/2)/3 a3 = ((āˆ’1)/2)(1/3) a3 = (āˆ’1)/6 Putting n = 4 in (1) a4 = š‘Ž_(4 āˆ’ 1 )/4 a4 = a3/4 a4 = ((āˆ’1)/6)/4 a4 = ( (āˆ’1)/6 )(1/4) a4 = (āˆ’1)/24 Putting n = 5 in (1) a5 = š‘Ž_(5 āˆ’ 1 )/5 a5 = (a4āˆ’)/5 a5 = ((āˆ’1)/24)/5 a5 = ((āˆ’1)/24)(1/5) a5 = (āˆ’1)/120 Hence first five terms of the sequence are -1, (āˆ’1)/2, (āˆ’1)/6, (āˆ’1)/24, and (āˆ’1)/120. The corresponding series is (-1) + ((āˆ’1)/2) + ((āˆ’1)/6) + ((āˆ’1)/24) + ((āˆ’1)/120) +……

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