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Transcript

Ex9.1 , 12 Write the first five terms of the following sequence and obtain the corresponding series: a1 = -1 , an = 𝑎_(𝑛−1)/𝑛 , n ≥ 2 It is given that a1 = -1, For a2 and onward, we have to use this formula an = 𝑎_(𝑛−1)/𝑛 Putting n = 2 in (1) a2 = 𝑎_(2−1)/2 = 𝑎_1/2 = (−1)/2 Putting n = 3 in (1) a3 = 𝑎_(3 − 1 )/3 a3 = (a2−)/3 a3 = ((−1)/2)/3 a3 = ((−1)/2)(1/3) a3 = (−1)/6 Putting n = 4 in (1) a4 = 𝑎_(4 − 1 )/4 a4 = a3/4 a4 = ((−1)/6)/4 a4 = ( (−1)/6 )(1/4) a4 = (−1)/24 Putting n = 5 in (1) a5 = 𝑎_(5 − 1 )/5 a5 = (a4−)/5 a5 = ((−1)/24)/5 a5 = ((−1)/24)(1/5) a5 = (−1)/120 Hence first five terms of the sequence are -1, (−1)/2, (−1)/6, (−1)/24, and (−1)/120. The corresponding series is (-1) + ((−1)/2) + ((−1)/6) + ((−1)/24) + ((−1)/120) +……

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.