Example 10 - Chapter 6 Class 11 Permutations and Combinations

Last updated at August 8, 2026 by

Example 10 - How many 4-digit numbers can be formed - Chapter 7 - Examples

part 2 - Example 10 - Examples - Serial order wise - Chapter 6 Class 11 Permutations and Combinations

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Example 10(Method 1) How many 4-digit numbers can be formed by using the digits 1 to 9 if repetition of digits is not allowed? n = Numbers from 1 to 9 = 9 r = 4 Required 4 digit number = 9P4 = 9!/((9 4)!) = 9!/5! = (9 8 7 6 5!)/5! = 3024 Example 10(Method 2) How many 4-digit numbers can be formed by using the digits 1 to 9 if repetition of digits is not allowed? Let the 4 digit number be Number of 4 digit numbers which can be formed = 9 8 7 6 = 3024

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