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Misc 1 - Chapter 6 Class 11 Permutations and Combinations
Last updated at August 10, 2026 by Teachoo
Both Permuation and combination
Chapter 6 Class 11 Permutations and Combinations
Concept wise
- Factorial
- Fundamental principal of counting
- Permutation formula
- Permutation- non repeating
- Permutation- repeating
- Combination formula
- Combination
-
Both Permuation and combination
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Transcript
Misc 1 How many words, with or without meaning, each of 2 vowels and 3 consonants can be formed from the letters of the word DAUGHTER? Number ways of selecting 2 vowels & 3 consonants = 3C2 × 5C3 = 3!/2!(3 − 2)! × 5!/3!(5 − 3)! = 3!/2!1! × 5!/3!2! = 30 Now, Each of these 5 letters can be arranged in 5 ways Number of arrangements = 5P5 = 5!/(5 − 5)! = 5!/0! = 5! = 5 × 4 × 3 × 2 × 1 = 120 Thus, Total number of words = Number of ways of selecting × Number of arrangements = 30 × 120 = 3600
