Last updated at May 29, 2018 by Teachoo

Transcript

Ex 5.1, 14 Express the following Expression in the form of a + ib. ((3 + i√5 ) (3 − i√5))/((√3 + √2 i) − (√3 − i√2) ) ((3 + i√(5 ) ) ( 3 − i√(5 )) )/((√3 + √2 i) − (√3 − 𝑖 √2 ) ) Using (a + b) (a - b) = a2 – b2 = ((3)^2 − ( i √5 )^2)/(√3 + √2 𝑖 − √3 + i √2) = (9 − i^2 × 5)/(√3 − √(3 )+ √2 𝑖 + 𝑖√2) Putting 𝑖2 = −1 = (9 − (−1) × 5)/( 0 + √2 𝑖 + 𝑖√2) = (9 + 5)/(√2 𝑖+ √(2 ) 𝑖) = 14/(2 √2 𝑖) = 14/(2√2 𝑖) ×(2√2 𝑖)/(2√2 𝑖) = (28√2 𝑖)/(4 × 2 × 𝑖^2 ) = (28 √(2 ) 𝑖)/(8 × 𝑖2) = (28√(2 ) 𝑖)/(8 ×−1) = (28√(2 ) 𝑖)/(− 8) = (− 7√(2 ) 𝑖)/2 = (− 7√(2 ))/2 𝑖 = 0 + ((− 7√(2 ))/2) 𝑖

Class 11

Important Question for exams Class 11

- Chapter 1 Class 11 Sets
- Chapter 2 Class 11 Relations and Functions
- Chapter 3 Class 11 Trigonometric Functions
- Chapter 4 Class 11 Mathematical Induction
- Chapter 5 Class 11 Complex Numbers
- Chapter 6 Class 11 Linear Inequalities
- Chapter 7 Class 11 Permutations and Combinations
- Chapter 8 Class 11 Binomial Theorem
- Chapter 9 Class 11 Sequences and Series
- Chapter 10 Class 11 Straight Lines
- Chapter 11 Class 11 Conic Sections
- Chapter 12 Class 11 Introduction to Three Dimensional Geometry
- Chapter 13 Class 11 Limits and Derivatives
- Chapter 14 Class 11 Mathematical Reasoning
- Chapter 15 Class 11 Statistics
- Chapter 16 Class 11 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.