Slide20.JPG

Slide21.JPG


Something went wrong!

The video couldn't load due to a technical hiccup.
But don't worry — our team is already on it, and we're working hard to get it back up ASAP.

Thanks for bearing with us!

Share on WhatsApp

Transcript

Ex5.1, 12 Find the multiplicative inverse of the Complex number √5 + 3𝑖 Multiplicative inverse of z = z – 1 Multiplicative inverse of z = 1/𝑧 Putting z = √5 + 3𝑖 multiplicative inverse of √5 + 3𝑖 = 1/(√5 + 3 𝑖) Rationalizing = 1/(√5 + 3𝑖) ×(√5 − 3𝑖)/(√5 − 3𝑖) = (√5 − 3𝑖)/(√5 + 3𝑖 )(√(5 )− 3𝑖) Using (a – b ) ( a + b ) = a 2 – b 2 = (√5 − 3𝑖)/((√5 )2− (3𝑖)2) "= " (√5 − 3𝑖)/(5 − 9𝑖2) Putting i 2 = −1 = (√5 − 3𝑖)/(5 − 9 (−1) ) = (√5 − 3𝑖)/(5 + 9 ) = (√5 − 3𝑖)/14 = (√5 )/14 − 3/14 𝑖

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo