Ex 5.1, 9 - Express in a + ib: (1/3 + 3i)3 - Complex numbers - Ex 5.1

  1. Chapter 5 Class 11 Complex Numbers
  2. Serial order wise
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Ex5.1, 9 Express the given Complex number in the form a + ib: (1/3+3๐‘–)^3 (1/3+3๐‘–)^3 It is the form ( a + b )3 ( a + b )3 = a3 + b3 + 3ab ( a + b ) Putting a = 1/3 ๐‘Ž๐‘›๐‘‘ ๐‘ = 3 i = (1/3 )^3+( 3๐‘–)3+3ร—1/3 ร—3๐‘– ( 1/3+3๐‘–) = 1/27 + (3)^3 (๐‘–)^3 + 3๐‘– ( 1/3+3๐‘–) = 1/27 + 27 ๐‘–^3 + 3๐‘– ( 1/3+3๐‘–) = 1/27 + 27 ๐‘–^3 + 3๐‘– ร— 1/3+3๐‘– ร— 3๐‘– = 1/27 + 27 ๐‘–^3+ ๐‘– + 9๐‘–2

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