Predict the output of the following code:
def Factorial (N) :
if N == 0 or N == 1:
return 1
else:
return N * Factorial (N-1)
X = 5
Y = Factorial (X)
print(Y)
X = Factorial (X-2)
print(X, end='?')
Answer:
Answer by student
120
6?
Detailed answer by teachoo
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- The question asks us to predict the output of the code. The code defines a function named Factorial that takes a parameter named N , which is a positive integer. The function returns the factorial of N , which is the product of all positive integers from 1 to N . The function uses recursion, which means it calls itself with a smaller argument until it reaches a base case. The base case is when N is 0 or 1, in which case the function returns 1. Otherwise, the function returns N multiplied by the factorial of N-1 .
- The code then assigns 5 to a variable named X and calls the Factorial function with X as an argument. It assigns the result to a variable named Y and prints it. To calculate the value of Y , we can use the following steps:
- Factorial (5) = 5 * Factorial (4)
- Factorial (4) = 4 * Factorial (3)
- Factorial (3) = 3 * Factorial (2)
- Factorial (2) = 2 * Factorial (1)
- Factorial (1) = 1 (base case)
- Factorial (2) = 2 * 1 = 2
- Factorial (3) = 3 * 2 = 6
- Factorial (4) = 4 * 6 = 24
- Factorial (5) = 5 * 24 = 120
- Therefore, Y is equal to 120 and it is printed on the first line of the output.
- The code then calls the Factorial function with X-2 as an argument and assigns the result to X . It prints X with a question mark at the end. To calculate the value of X , we can use the following steps:
- X-2 = 5-2 = 3
- Factorial (3) = 3 * Factorial (2)
- Factorial (2) = 2 * Factorial (1)
- Factorial (1) = 1 (base case)
- Factorial (2) = 2 * 1 = 2
- Factorial (3) = 3 * 2 = 6
- Therefore, X is equal to 6 and it is printed on the second line of the output with a question mark.
So, the output of the code is:
120
6?
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