Question 20 - Sample Paper 1 by Teachoo - Teachoo Sample Paper

The code given below accepts a number as an argument and returns True if the number is prime, and False otherwise. Observe the following code carefully and rewrite it after removing all syntax and logical errors. Underline all the corrections made.

def is_prime(n):

  if n < 2:

  return False

  for i in range(2, n)

     if n % i = 0:

       return false

     else:

       return True

Answer:

Answer by student

Detailed answer by teachoo

The code given below accepts a number as an argument and returns True if the number is prime, and False otherwise. A prime number is a natural number that has exactly two factors, 1 and itself. To check if a number is prime, we can use a loop to iterate over all the possible factors from 2 to n-1 and see if any of them divides the number evenly. If yes, then the number is not prime and we can return False. If no, then the number is prime and we can return True.

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The code has some syntax and logical errors that need to be fixed. Here are the corrections made:

• The indentation of the code blocks after the if and else statements should be consistent and follow the Python style guide. Indentation is important in Python as it defines the scope of the code blocks. The corrected code has four spaces for each level of indentation.
• The range function requires a colon at the end to indicate the start and end of the range. The colon is missing in the original code and should be added after n .
• The comparison operator for equality in Python is == , not = . The = operator is used for assignment, not comparison. The original code uses = in the if statement and should be replaced with == .
• The capitalization of the Boolean values True and False should be consistent and follow the Python convention. The original code uses lowercase false in one place and should be corrected to uppercase False.

So, the corrected code is:

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