Last updated at December 13, 2024 by Teachoo
Transcript
Example 6 The marks distribution of 30 students in a mathematics examination are given in Table 14.3 of Example 1. Find the mode of this data. Also compare and interpret the mode and the mean. Mode = l + (šš āšš)/(ššš āšš āšš) Ć h Modal class = Interval with highest frequency = 40 ā 55 where l = lower limit of modal class h = class-interval f1 = frequency of the modal class f0 = frequency of class before modal class f2 = frequency of class after modal class Putting values in equation Mode = l + (š1 āš0)/(2š1 āš0 āš2) Ć h = 40 + (7 ā3)/(2(7)ā3ā6) Ć 15 = 40 + 4/(14 ā9) Ć 15 = 40 + 4/5 Ć 15 = 40 + 4 Ć 3 = 40 + 12 = 52 ā“ Mode = 52 So, maximum number of students obtained 52 marks & Mean = 62 Therefore, on an average, the students got 62 marks.