Ex 13.1, 8 - A class teacher has the absentee record of - Ex 13.1 - Ex 13.1

part 2 - Ex 13.1, 8 - Ex 13.1 - Serial order wise - Chapter 13 Class 10 Statistics
part 3 - Ex 13.1, 8 - Ex 13.1 - Serial order wise - Chapter 13 Class 10 Statistics

part 4 - Ex 13.1, 8 - Ex 13.1 - Serial order wise - Chapter 13 Class 10 Statistics part 5 - Ex 13.1, 8 - Ex 13.1 - Serial order wise - Chapter 13 Class 10 Statistics part 6 - Ex 13.1, 8 - Ex 13.1 - Serial order wise - Chapter 13 Class 10 Statistics

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Ex 13.1, 8 (Method 1 – Direct Method) A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent. Here Class Size is not same, So, we solve by Direct Method š‘„ Ģ… = 499/40 š’™ Ģ… = 12.48 Therefore, Mean number of days a student was absent is 12.48 days Ex 13.1, 8 (Method 2 – Step Deviation Method) A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent. Ex 13.1, 8 (Method 2 – Step Deviation Method) A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent. Mean(š‘„ Ģ…) = a + h Ɨ (āˆ‘ā–’š’‡š’Šš’–š’Š)/(āˆ‘ā–’š’‡š’Š) Where a = Assumed Mean Let h = Class interval Also, āˆ‘ā–’š’‡š’Š = 40 āˆ‘ā–’š’‡š’Šš’–š’Š = āˆ’90.5 Putting values in formula Mean(š’™ Ģ…) = a + h Ɨ (āˆ‘ā–’š’‡š’Šš’–š’Š)/(āˆ‘ā–’š’‡š’Š) š‘„ Ģ… = 17 + 2 Ɨ (āˆ’90.5)/40 š‘„ Ģ… = 17 – 4.525 š’™ Ģ… = 12.475 Therefore, Mean number of days a student was absent is 12.48 days

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