Ex 14.1, 8 - A class teacher has the absentee record of - Ex 14.1

Ex 14.1, 8 - Chapter 14 Class 10 Statistics - Part 2
Ex 14.1, 8 - Chapter 14 Class 10 Statistics - Part 3

Ex 14.1, 8 - Chapter 14 Class 10 Statistics - Part 4 Ex 14.1, 8 - Chapter 14 Class 10 Statistics - Part 5 Ex 14.1, 8 - Chapter 14 Class 10 Statistics - Part 6

  1. Chapter 14 Class 10 Statistics (Term 2)
  2. Serial order wise

Transcript

Ex 14.1, 8 (Method 1 – Direct Method) A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent. Here Class Size is not same, So, we solve by Direct Method Putting values in formula Mean(π‘₯ Μ…) = (βˆ‘β–’π‘“π‘–π‘₯𝑖)/(βˆ‘β–’π‘“π‘–) π‘₯ Μ… = 499/40 𝒙 Μ… = 12.48 Therefore, Mean number of days a student was absent is 12.48 daysEx 14.1, 8 (Method 2 – Step Deviation Method) A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent. Here Class Size is not same… So, in Step Deviation Method Mean(π‘₯ Μ…) = a + h Γ— (βˆ‘β–’π’‡π’Šπ’–π’Š)/(βˆ‘β–’π’‡π’Š) We use a value of h which can divide 𝑑𝑖 = π‘₯𝑖 βˆ’ a Mean(π‘₯ Μ…) = a + h Γ— (βˆ‘β–’π’‡π’Šπ’–π’Š)/(βˆ‘β–’π’‡π’Š) Where a = Assumed Mean Let h = Class interval Also, βˆ‘β–’π’‡π’Š = 40 βˆ‘β–’π’‡π’Šπ’–π’Š = βˆ’90.5 Putting values in formula Mean(𝒙 Μ…) = a + h Γ— (βˆ‘β–’π’‡π’Šπ’–π’Š)/(βˆ‘β–’π’‡π’Š) π‘₯ Μ… = 17 + 2 Γ— (βˆ’90.5)/40 π‘₯ Μ… = 17 – 4.525 𝒙 Μ… = 12.475 Therefore, Mean number of days a student was absent is 12.48 days

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.