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Ex 14.1, 3 - Daily pocket allowance of children of a locality

Ex 14.1, 3 - Chapter 14 Class 10 Statistics - Part 2
Ex 14.1, 3 - Chapter 14 Class 10 Statistics - Part 3

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Ex 14.1, 3 The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs.18. Find the missing frequency f. Mean(𝑥 ̅) = a + (∑▒𝒇𝒊𝒅𝒊)/(∑▒𝒇𝒊) Where a = Assumed Mean h = Class interval = 18 = 13 – 11 = 2 Putting values in formula Mean = 18 + (2𝑓 − 40)/(44 + 𝑓) 18 = 18 + (2𝑓 − 40)/(44 + 𝑓) 18 − 18 = (2𝑓 − 40)/(44 + 𝑓) 0 = (2𝑓 − 40)/(44 + 𝑓) 0 = 2𝑓−40 2𝑓=40 f = 40/2 f = 20

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.