Ex 14.1, 3 - Daily pocket allowance of children of a locality

Ex 14.1, 3 - Chapter 14 Class 10 Statistics - Part 2
Ex 14.1, 3 - Chapter 14 Class 10 Statistics - Part 3

  1. Chapter 14 Class 10 Statistics (Term 2)
  2. Serial order wise

Transcript

Ex 14.1, 3 The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs.18. Find the missing frequency f. Mean(๐‘ฅ ฬ…) = a + (โˆ‘โ–’๐’‡๐’Š๐’…๐’Š)/(โˆ‘โ–’๐’‡๐’Š) Where a = Assumed Mean h = Class interval = 18 = 13 โ€“ 11 = 2 Putting values in formula Mean = 18 + (2๐‘“ โˆ’ 40)/(44 + ๐‘“) 18 = 18 + (2๐‘“ โˆ’ 40)/(44 + ๐‘“) 18 โˆ’ 18 = (2๐‘“ โˆ’ 40)/(44 + ๐‘“) 0 = (2๐‘“ โˆ’ 40)/(44 + ๐‘“) 0 = 2๐‘“โˆ’40 2๐‘“=40 f = 40/2 f = 20

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.