Question 1 (i) - Chapter 7 Class 10 Coordinate Geometry (Important Question)

Last updated at Dec. 13, 2024 by

Question 1 (i) Class 10 - Find the area of the triangle whose vertices - Area of Triangle when coordinates are given

part 2 - Question 1 (i) - Area of Triangle when coordinates are given - Serial order wise - Chapter 7 Class 10 Coordinate Geometry

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Ex 7.3 , 1 Find the area of the triangle whose vertices are : (i) (2, 3), (–1, 0), (2, – 4) Let the two points be A(2, 3) , B(−1, 0) & C(2, −4) Area of triangle ABC = 1/2 [ x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2) ] Here x1 = 2 , y1 = 3 x2 = −1 , y2 = 0 x3 = 2 , y3 = −4 Putting values Area of triangle ABC = 1/2 [2(0 – (−4)) + (−1)(−4 – 3 ) + 2(3 – 0)] = 1/2 [ 2(4) + (−1)(– 7 ) + 2(3)] = 1/2 [8 + 7 + 6] = 1/2 [21] = 10.5 square units

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo