(d) A diamond is immersed in such a liquid which has its refractive index with respect to air as greater than the refractive index of water with respect to air. Then the critical angle of diamond-liquid interface as compared to critical angle of diamond -water interface will 

(i) depend on the nature of the liquid only 

(ii) decrease 

(iii) remain the same 

(iv) increase.  

Answer

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Transcript

Question 12 (Choice 2) (d) A diamond is immersed in such a liquid which has its refractive index with respect to air as greater than the refractive index of water with respect to air. Then the critical angle of diamond-liquid interface as compared to critical angle of diamond -water interface will (i) 𝑛_1<𝑛_2 (ii) 𝑛_1=𝑛_2 (iii) 𝑛_1≪𝑛_2 (iv)𝑛_1>𝑛_2 Given, 𝜇_𝑙𝑖𝑞𝑢𝑖𝑑 = 𝜇_𝑤𝑎𝑡𝑒𝑟 Critical angle of diamond with liquid 𝐶′=sin^(−1)⁡〖𝜇_𝑙𝑖𝑞𝑢𝑖𝑑/𝜇_𝑑𝑖𝑎𝑚𝑜𝑛𝑑 〗 Critical angle of diamond with water 𝐶′=sin^(−1)⁡〖𝜇_𝑤𝑎𝑡𝑒𝑟/𝜇_𝑑𝑖𝑎𝑚𝑜𝑛𝑑 〗 sin⁡𝐶>sin⁡𝐶′ 𝐶>𝐶′ So the correct answer is (iv)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.