(a) Draw a ray diagram of a compound microscope for the final image formed at least distance of distinct vision? 

Answer

Diagram of Compound Microscope for the final image formed at D

RAY DIAGRAM - COMPOUND MICROSCOPE- FINAL IMAGE AT D.jpg

(b) An angular magnification of 30X is desired using an objective of focal length 1.25 cm and an eye piece of focal length 5 cm. How will you set up the compound microscope for the final image formed at least distance of distinct vision? 

Answer

part 2 - Question 8 (Choice 1) - CBSE Class 12 Sample Paper for 2022 Boards [Term 2] - Physics - Solutions to CBSE Sample Paper - Physics Class 12 - Physics Class 12

part 3 - Question 8 (Choice 1) - CBSE Class 12 Sample Paper for 2022 Boards [Term 2] - Physics - Solutions to CBSE Sample Paper - Physics Class 12 - Physics Class 12 part 4 - Question 8 (Choice 1) - CBSE Class 12 Sample Paper for 2022 Boards [Term 2] - Physics - Solutions to CBSE Sample Paper - Physics Class 12 - Physics Class 12

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Question 8 (b) (Choice 1) An angular magnification of 30X is desired using an objective of focal length 1.25 cm and an eye piece of focal length 5 cm. How will you set up the compound microscope for the final image formed at least distance of distinct vision? π‘š_0=30,𝑓_0=1.25 π‘π‘š,𝑓_𝑒=5 π‘π‘š When image is formed at least distance of distinct vision D = 25 cm Angular magnification of eyepiece π‘š_𝑒=(1+𝐷/𝑓_𝑒 )=1+25/5=6 Total Angular magnification, π‘š=π‘š_π‘œ π‘š_𝑒 π‘š_π‘œ=π‘š/π‘š_𝑒 =30/6=5 As the objective lens forms the real image, π‘š_π‘œ= 𝑣_π‘œ/𝑒_π‘œ =βˆ’5 𝑣_π‘œ=βˆ’5𝑒_π‘œ Using lens equation, 𝑒_π‘œ=βˆ’1.5 π‘π‘š 𝑣_π‘œ=βˆ’5Γ—(βˆ’1.5)π‘π‘š =7.5 π‘π‘š Given 𝑉_𝑒=βˆ’π·=25 π‘π‘š, 𝑓_𝑒=+5 π‘π‘š, 𝑒_𝑒= ? using again lens equation 𝑒_𝑒=25/6 Thus, object is to be placed at 1.5 cm from the objective and separation between the two lenses should be 𝐿=𝑣_π‘œ+𝐼𝑒_𝑒 𝑰=𝟏𝟏.πŸ”πŸ• cm

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